Mathematics: How much of a radioactive kind of niobium will be left after 105 days if you start with 3,920 grams and the half-life is 35 days?

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How much of a radioactive kind of niobium will be

alexisbaronetp85kek

18.05.2021

"490 grams" would be the correct solution.

Step-by-step explanation:

The given values are:

Half time,

T = 35 days

Total time,

t = 105 days

As we know,

⇒ $A=A_o(\frac{1}{2} )^{\frac{t}{T} }$

On substituting the values, we get

⇒ $=3920\times (\frac{1}{2})^{\frac{105}{35} }$

⇒ $=3920\times (0.5)^3$

⇒ $=3920\times 0.125$

⇒ $=490 \ grams$

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