Mathematics: How to find the interior angles of a polygon

How to find the interior angles of a polygon

mchpalmer

30.05.2020

To find the interior angles of the polygon use the following formula:

180 ( n-2 )

n is the number of sides in the polygon.

Hope this helps :)

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libertycooper

29.03.2020

1. Each term in this polynomial has a common factor of 3x^3 :

12x^6-9x^4+18x^3=3x^3(4x^3-3x+6)

2. Not sure what the "vertical method" is, but I would guess it refers to some way of visualizing the distributive property.

(3x-5)(2x^2+7x-3)=3x(2x^2+7x-3)-5(2x^2+7x-3)

(3x-5)(2x^2+7x-3)=(6x^3+21x^2-9x)+(-10x^2-35x+15)

(3x-5)(2x^2+7x-3)=6x^3+11x^2-44x+15

3. You can use the same approach as in (2), or recall that (a+b)^2=a^2+2ab+b^2 :

(5x-4y)^2=(5x)^2+2(5x)(-4y)+(-4y)^2

(5x-4y)^2=25x^2-40xy+16y^2

4. Recall that a difference of squares can be factored as a^2-b^2=(a-b)(a+b) . So

(2x^2-7)(2x^2+7)=(2x^2)^2-7^2

(2x^2-7)(2x^2+7)=4x^4-49

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