Mathematics: How would you solve this equation? show steps

How would you solve this equation? show steps

Ответ:

obastwin2

11.01.2022

Simple....

you have: $3x= \sqrt{12-12x}$

So...first you know you're trying to find x..

But, you have a square root on one side...to remove this you'd have to square both sides--->>>

$(3x)^{2} = \sqrt{12-12x} ^{2}$

Leaving you with....

$9x^{2} =12-12x$

Move the terms over and set it equal to zero.

-->>

$9x^{2}+12x-12=0$

Factor out a 3...

$3( 3x^{2} +4x-4=0)$

What multiplies to -12 and adds to 4?

6*-2=-12

6+-2=4

Leaving you with...

3(3x-2)(x+2)=0

Remember you're solving for 0....

3x-2=0

3x-2=0
+2 +2

3x=2

$\frac{3x}{3} = \frac{2}{3}$

x= $\frac{2}{3}$

Then-->>

x+2=0

x+2=0
-2 -2

x=-2

Thus, your answer.

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Ответ:

joelpimentel

08.06.2021

Mathematics

Domain: - infinity, + infinity. Range All real numbers less than -3

Step-by-step explanation:

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How would you solve this equation? show steps

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