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chilanka
05.07.2019 •
Mathematics
Hurry 30 pts what is the equation of the graphed line written in standard form? a. 3x + y = –5 b. x + 3y = –5 c. 3x – 5y = –15 d. 5x – 3y = 15
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Ответ:
D
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (3, 0 ) and (x₂, y₂ ) = (0, - 5 )
m =
= ![\frac{5}{3}](/tpl/images/0053/6243/dcb5a.png)
line crosses y-axis at (0, - 5 ) hence c = - 5
y =
x - 5 ← in slope-intercept form
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
rearrange slope-intercept form into standard form
multiply all terms by 3
3y = 5x - 15 ( subtract 3y and add 15 to both sides )
5x - 3y = 15 ← in standard form → D
Ответ:
1/2 mile
Step-by-step explanation:
If you add 1/4 and 1 3/4, you get 2. Then, subtract 2 1/2-2=1/2