I 1. At time t in seconds, a particle's distance s(t), in micrometers (um), from a point is given by
s(t) =
-1
What is the average velocity of the particle from t = 2 to t = 4?

70 ft per sec going upward 3 sec from 6 ft high should reach 216 ft, but unfortunately gravity is pulling it and at some point it starts to go backward (at 2.176 second), so to compensate the upward slowing down and distance dropped, use -32.176 times 3 square times 1/2 = -144.792 which is the natural drop distance if the football is released mid air without a initial speed after 3 seconds. 216 - 144.792 = 71.208 ft high.