I am not understanding the question.

(C) 16 units to the right

Step-by-step explanation:

Position is the integral of velocity with respect to time:

x = ∫ v dt

x = ∫ (t − ∛t) dt

x = ½ t² − ¾ t^(⁴/₃) + C

At time t = 0, x = -4.

-4 = ½ (0)² − ¾ (0)^(⁴/₃) + C

-4 = C

So the position equation is:

x = ½ t² − ¾ t^(⁴/₃) − 4

At time t = 8:

x = ½ (8)² − ¾ (8)^(⁴/₃) − 4

x = 32 − 12 − 4

x = 16

The particle is 16 units to the right of the origin.

There is an infinite number of numbers between 1 and 1.01 on the number line. The correct answer should theoretically be: 1 < n < 1.01.