user1234573
20.11.2020 •
Mathematics
I need help I will give brainless
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Ответ:
The required length of the wire is 15.637 m
The power dissipated is 1,216 W
Explanation:
Length (L) = resistance×area/resistivity
Resistance = 19 ohm
Area = 0.001276 in^2 = 0.001276in^2 × (2.54cm/1in)^2 = 8.23×10^-3 cm^2
Resistivity = 1×10^-4 ohm-cm
L = 19×8.23×10^-3/1×10^-4 = 1563.7 cm = 1563.7/100 = 15.637 m
Power = I^2 R = 8^2 × 19 = 64×19 = 1,216 W