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kingnya63
16.02.2020 •
Mathematics
I need help this is very hard please
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Ответ:
7 + 6 = 9 + 4
16 - 7 = 3 + 6
20 x 6 = 60 x 2
2 x (3 + 5) = 20 - 4
3 + (3 x 6) = 3 + 3 + 15
Solution:Given that, we have to find the missing numbers in each equation
First equation:Let the unknown be "x"
7 + x = 9 + 4
Solve the right side of equation, 9 + 4 = 13
7 + x = 13
x = 13 - 7
x = 6
Second equation:Let the unknown be "x"
16 - 7 = 3 + x
Solve the left side of equation, 16 - 7 = 9
9 = 3 + x
x = 9 - 3
x = 6
Third Equation:![D \times 6 = 60 \times 2\\\\D \times 6 = 120\\\\D = \frac{120}{6}\\\\D = 20](/tpl/images/0512/6785/6e473.png)
Fourth Equation:![2 \times (3 + 5) = x - 4\\\\Solve\ for\ brackets\\\\2 \times 8 = x - 4\\\\16 = x - 4\\\\x = 16 + 4\\\\x = 20](/tpl/images/0512/6785/db857.png)
Fifth Equation:Let the unknown be "x"
Ответ: