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lIechonoxIl
08.11.2020 •
Mathematics
I need help understanding this ASAP plz, I have a quiz over this next week
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Ответ:
Step-by-step explanation:
With any two points, you can find the line between them with:
#1:
(-1, 1) -> (1, 3)![m = \frac{3-1}{1-(-1)} = 1, 3 = 1(1) + b, b = 2, y = x + 2](/tpl/images/0878/9489/e08ac.png)
(3, 4) -> (0, 2)![m = \frac{4-2}{3-0} = \frac{2}{3}, 2 = \frac{2}{3}(0) + b, y = \frac{2}{3}(x)+2](/tpl/images/0878/9489/a3a41.png)
(0, 1) -> (3, 3)![m = \frac{3-1}{3-0} = \frac{2}{3}, 1 = 2/3(0) + b, y = \frac{2}{3}(x) + 1](/tpl/images/0878/9489/b13fc.png)
Lines b and c are parallel because they have the same slopes
#2 is a bit easier
a: 2y = x + 12,![y = \frac{1}{2}(x) + 6](/tpl/images/0878/9489/b4ee0.png)
b:2y - x = 5,![y = \frac{1}{2}(x) + \frac{5}{2}](/tpl/images/0878/9489/85a8d.png)
c: 2y + x = 4,![y = \frac{-1}{2}(x) + 2](/tpl/images/0878/9489/c1594.png)
Since lines a and b have the same slope, they are parallel
#3:
(1, 3), y = 2x - 5
We have to find a line with a slope of 2 that passes through the two points
#4:
(-2, 1) , y = -4x + 3
We have to find a line with a slope of-4 that passes through the line
#5:
(-2, 3) (1, -1),![m = \frac{3-(-1)}{-2-1} = \frac{-4}{3}, 3 = \frac{8}{3} + b, b = \frac{1}{3}, y = \frac{-4x}{3} + \frac{1}{3}](/tpl/images/0878/9489/715ce.png)
(-3, 1) (1, 4),![m = \frac{4-1}{1-(-3)} =\frac{3}{4}, 4 = \frac{3(1)}{4} + b, y = \frac{3}{4}(x) + \frac{13}{4}](/tpl/images/0878/9489/dfe55.png)
(0, 2) (3, -2)![m = \frac{2-(-2)}{0-3} = \frac{-4}{3} , 2 = b, y = \frac{-4}{3}(x) + 2](/tpl/images/0878/9489/ca6bb.png)
Since lines c and b have negative reciprocal slopes, they are perpendicular
#6:
a: y = -4x + 7
b: x = 4y + 2,![y = \frac{x}{4} - \frac{1}{2}](/tpl/images/0878/9489/0f2e5.png)
c: -4y + x = 3,![y = \frac{x}{4} - \frac{3}{4}](/tpl/images/0878/9489/9de6d.png)
since lines a and c have negative reciprocal slopes, they are perpendicular
Ответ:
8k - 72
Step-by-step explanation:
8(k-9) = 8k - 72 (or 8k + -72, if you prefer)