I need to find the sum

2(y^2 +4y+2)

(y+1)^2(y+2)      

Step-by-step explanation:

2y                        4

 +

y^2 +2y+1       y^2 +3y+2

Factor the denominators

2y                        4

 +

(y+1)(y+1)       (y+2)(y+1)

Get a common denominator

2y   (y+2)          4(y+1)

 +

(y+1)^2(y+2)       (y+2)(y+1)^2

Distribute in the numerator

2y^2+4y          4y+4

 +

(y+1)^2(y+2)       (y+2)(y+1)^2

Combine like terms

2y^2 +8y+4

(y+1)^2(y+2)

Factor out a 2

2(y^2 +4y+2)

(y+1)^2(y+2)      

  24/25

Step-by-step explanation:  sinB= perpendicular/hypotenuse

                                                      =  side opposite to angle B/hypotenuse

                                                      = AC/AB

                                                      = 24/25