I need to solve this system of equations, how do I do that?
3x-4y=20
y=3/4x-5

Is is Infinitely many solutions so 0=0

Step-by-step explanation:

First we have to rearrange/simplify the equations:

Equation 1: 4y - 3x = -20

Equation (2):  y - 3x/4  = -5

Then you remove the fractions by multiplication:

Multiply equation (2) by 4

The Equations now look like this:

Equation 1: 4y - 3x = -20

Equation (2): 4y - 3x = -20

Solve for y on Equation (2):

y = 3x/4 - 5

Then plug in this for the y in Equation 1 and then solve:

4•(3x/4-5) - 3x = -20

Therefore the answer leads to:

Infinitely many solutions, 0=0

Hope this helped :')

2c^2

Step by step explanation: