![JohnnyR7057](/avatars/20006.jpg)
JohnnyR7057
03.03.2020 •
Mathematics
I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and provide statistical explanations. Please help me and answer these before 9: 15 in the morning EST on March 3rd, 2020.
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Ответ:
use product and sum method
product = -96
sum = -20
numbers needed = ( -24 , 4)
n - 24 = 0
n + 4 = 0
hence n = 24 and n = -4
Question 2in the form![ax^{2} +bx +c = 0](/tpl/images/0532/1157/5491f.png)
=![x^{2} +12x - 48](/tpl/images/0532/1157/0e427.png)
make use of the formula :
replace values to make 2 equations :
1.
= 3.17
2.
= -15.2
hence x = 3.17 and x = -15.2
Question 3use product and sum method
product = 40
sum = -14
numbers needed = (-10 , -4)
x - 10 = 0
x - 4 = 0
hence x = 10 and x = 4
Question 4in the form![ax^{2} +bx +c = 0](/tpl/images/0532/1157/5491f.png)
this becomes![5b^{2} -20b-18-7](/tpl/images/0532/1157/48b5c.png)
=![5b^{2} -20b-25](/tpl/images/0532/1157/ad8a8.png)
can simplify by 5
=![b^{2} -4b-5 =0\\](/tpl/images/0532/1157/dbf3c.png)
use product and sum method
product = -5
sum = -4
numbers needed (-5 , 1)
b-5 = 0
b + 1 = 0
hence b = 5 and b = -1
Ответ:
Step-by-step explanation:
1) n² - 20n - 96 = 0
n² - 20n + (- 20/2)² = 96 + (- 20/2)²
(n - 10)² = 96 + 100
(n - 10)² = 196
Taking square root of both sides
n - 10 = √196 = 14
n = 14 + 10
n = 24
2) x² + 12x = 48
x² + 12x + (12/2)² = 48 + (12/2)²
(x + 6)² = 48 + 36 = 84
Taking square root of both sides,
x + 6 = 9.2
x = 9.2 - 6
x = 3.2
3) x² - 14x + 40 = 0
x² - 14x = - 40
x² - 14x + (- 14/2)² = - 40 + (- 14/2)²
(x - 7)² = - 40 + 49 = 9
Taking square root of both sides,
x - 7 = 3
x = 3 + 7
x = 10
4) 5b² - 20b - 18 = 7
5b² - 20b = 7 + 18
5b² - 20b = 25
Dividing both sides by 5, it becomes
b² - 4b = 5
b² - 4b + (-4/2)² = 5 + (-4/2)²
(b - 2)² = 5 + 4 = 9
Taking square root of both sides
b - 2 = 3
b = 3 + 2
b = 5
Ответ: