![masie03](/avatars/31918.jpg)
masie03
30.09.2019 •
Mathematics
I've tried out this question so many different ways and i haven't been able to get it. i put 320 ft/s into the original equation to get t (time) and plugged that value into the derivative of the ogival which is the velocity. would be greatly appreciated. this is college calculus.
Solved
Show answers
More tips
- C Cities and Countries How to Easily and Quickly Obtain a Schengen Visa?...
- F Food and Cooking Red Caviar: How to Choose the Best?...
- C Computers and Internet Clearing Cache: How to Speed Up Your Browser...
- S Style and Beauty How are artificial nails removed?...
- S Style and Beauty Secrets of Tying a Pareo: 5 Ways...
- F Food and Cooking Everything You Need to Know About Pasta...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
Answers on questions: Mathematics
- M Mathematics 2. Jon pours the contents of Container 1 and Container 3 above into an empty bucket. How much liquid is in the bucket after he pours the liquid?...
- M Mathematics Write an expression in simplified form for the area of the rectangle. Show work!...
- M Mathematics Number 5 please!! I am very confused...
- M Mathematics WILL GIVE BRAINLIEST 4cos4(x)-5cos2(x)+1=0 from[0,2pi] If you could can you give steps please...
- M Mathematics The LCMS W basketball team is selling tickets to Christmas tournament. The ratio of adult to children tickets that have been sold is 6:1. If they have sold a total...
Ответ:
a)The maximum (or minimum) is reached when the derivative of s = 0
s' = 144 - 32t = 0 and t= 9/2 or 4.5 second (time needed to reach the max
Now plug t= 4.5 in the original equation and you will find s = 324 ft
(Why it's a max and not a minimum: because 2nd derivative is negative and equals s" = -32)
b) Velocity of the ball: distance (up) s=320 ft, time that means:
320 =144t - 16t² (solve for x) -16t²+144t-320 = 0, t₁ =4 and t₂ =5 (t₂ is not valid since max time to reach summit is 4.5) so t =4s , distance = 320. so the velocity at 320ft is 320/4 = 80 ft/s
c) Due to the symmetry of the parabola, the velocity at 320 ft on its way down = 80 ft/s
Ответ:
It would be about 0.035274
Step-by-step explanation:
For an approximate result, divide the mass value by 28.35
Hope this helps