I will Brainliest. Plz anyone don't scam if it so I will report then the users account will be got deleted. Solve All 5 problem and Explain deep about Question No. 5

Step-by-step explanation:

i)  1

ii) see attached

iii) as x goes from 0 to 2, y decreases parabolically from 1 to an acme at -3

iv) y = (x - 2)² - 3

v) -3 < t < 1

if t < -3 no intersection occurs between y = t and y = (x - 2)² - 3

if t = -3, y = t intersects the curve at only one point, (2, -3)

if -3 < t < 1 there exist two intersecting points with positive x values

if t = 1 there exist only one positive x value intersection as the other is at (0, 1) and 0 is neither positive nor negative.

if t > 1 there is one positive x value intersection and one negative x value intersection.

I think it would be 'e3'

Step-by-step explanation: