luusperezzz
15.04.2020 •
Mathematics
Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be represented by the function h(t)=-16t+20t. What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2 seconds
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Ответ:
Hence the rate of ascent at t=1/2 is 12 ft/sec
Step-by-step explanation:
Given:
Height function as h(t)=-16t^2+20t
To find:
Velocity at t=1/2. i.e. Average rate of ascent
Solution:
Average rate is given by
V=f(t)-f(a)/(t-a)
now here t=1/2 and a=0
Hence Equation becomes
V=f(1/2)-f(0)/(1/2-0)
So at t=1/2
f(1/2)=-16(1/2)^2+20(1/2)
=-4+10
=6 fts
Now ,t=0
f(0)=16(0)^2+20(0)
=0 ft
Hence V=f(1/2)-f(0)/(1/2-0)
V=(6-0)/(1/2-0)
V=6*2
V=12 ft/sec
Ответ:
2009$ left if you add 125+345+21 is 491 then take away 491 from 2500 and get 2009
pls mark Brainliest