Identify the center and radius of the circle..

B

Step-by-step explanation:

(x-h)^2 + (y-k)^2 = r^2 ; here (h,k) is co-ordinate of the center and r is the radius.

So, comparing this equation wth the given one,

we get,  h = -4, k = 2, r = 4

[If there's any mistake, please inform me]

(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous