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Savagepanda911

04.12.2020 •

Mathematics

Identify the outputs if the function rule is 2x - 5 and the inputs are 5,10,15

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Ответ:

mari8493

11.02.2022

15

Step-by-step explanation:

that is the answer

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Ответ:

tjuicy1

07.09.2020

The powers of a,b and c for the given expression

$\frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}=a^{-22}b^{20}c^0}$ is -22,20 and 0 respectively

Step-by-step explanation:

Given expression is $\frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}$

To find the powers of a,b and c:

$\frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}=\frac{(a^{-5})^2(b^7)^2(c^3)^2}{(a^4)^3(b^{-2})^3(c^2)^3}$ ( using the property (ab)^m=a^m.b^m )

$=\frac{a^{-10}b^{14}c^6}{a^{12}b^{-6}c^6}$ ( using the property $(a^m)^n=a^{mn}$ )

$=a^{-10}b^{14}c^6.a^{-12}b^{6}c^{-6}$ ( using the property $\frac{1}{a^m}=a^{-m}$ )

$=a^{-10-12}b^{14+6}c^{6-6}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=a^{-22}b^{20}c^{0}$

Therefore $\frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}=a^{-22}b^{20}c^{0}$

The powers of a,b and c for the given expression

$\frac{(a^{-5}b^7c^3)^2}{(a^4b^{-2}c^2)^3}=a^{-22}b^{20}c^0}$ is -22,20 and 0 respectively

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