Idon't know how to solve.. show work3x^3 +7x^2 +x -2

This is a cubic form. I am assuming this should be factored.

With cubics like this it's worthwhile trying to find one root by simply guessing. My guess that worked out is x=-2

To verify:

3(-2)^3+7(-2)^2+(-2)-2 = 0   -> so -2 is a root and we get the first factor: (x+2)

Next we divide the cubic by the factor (x+2). I let you do the division. Here is the result

(3x^3 +7x^2 +x -2):(x+2) = (3 x^2 + x - 1)

(3 x^2 + x - 1) is a quadratic form and you can use the quadratic formula to get the two other roots. I got  .

So the entire cubic is now factored as follows:

(6 - 8t)(6t - 4t²) / ((6t - 4t²)² + 64)⁰‧⁵