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katerin4738
31.10.2019 •
Mathematics
Idon't understand how to make it into a graphing form? how do you find the center and radius? (i'm confused because it has a 4x^2 and 4y^2 idk what to do with them
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Ответ:
Center = (2, 3) radius =![\bold{\dfrac{1}{2}}](/tpl/images/0354/2420/ae810.png)
Step-by-step explanation:
When both the x² and y² values are equal and positive, the shape is a circle. Complete the square to put the equation in format:
(x-h)² + (y-k)² = r² where
(h, k) is the vertexr is the radius1) Group the x's and y's together and move the number to the right side
4x² - 16x + 4y² - 24y = -51
2) Factor out the 4 from the x² and y²
4(x² - 4x ) + 4(y² - 6y ) = -51
3) Complete the square (divide the x and y value by 2 and square it)
= 4(x - 2)² + 4(y - 3)² = -51 + 4(-2)² + 4(-3)²
= 4(x - 2)² + 4(y - 3)² = -51 + 4(4) + 4(9)
= 4(x - 2)² + 4(y - 3)² = -51 + 16 + 36
= 4(x - 2)² + 4(y - 3)² = 1
4) Divide both sides by 4
Ответ: