Mathematics: If 14 g of a radioactive substance are present initially and 7 yr later only 7 g remain, how much of the substance will be present after 17 yr?

If 14 g of a radioactive substance are present - id141744516, nettyshaf202406

Ответ:

laywah4

30.12.2021

2.60 gr

Step-by-step explanation:

We need to consider the function $P(t) = P_oe^{kt}$ where Po is the initial substance k is the rate of decay and t is the time

We know that P_o = 14 and at the 7 th year P(t) is 7

This means

$7 = 14e^{7k}$

We solve for k

$\frac{7}{14} = e^{7k}\\\\\ln (\frac{7}{14}) = 7k\\\\k = \frac{\ln (7/14)}{7} = -0.099\\\\Then \ P(t) = 14e^{-0.099t}\\\\Now \ we \ take \ t = 17\\\\P(17) = 14e^{(-0.099)(17)} = 2.60$

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Ответ:

lexieforlife911

14.04.2022

Mathematics

Scale factor = 3

Step-by-step explanation:

Scale factor used for the dilation = the ratio of the corresponding side length of the new figure to the side length of the original figure

Scale factor = B'C'/BC

B'C' = 9 units

BC = 3 units

Scale factor = 9/3 = 3

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If 14 g of a radioactive substance are present initially and 7 yr later only 7 g remain, how much of the substance will be present after 17 yr?

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