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ladybugys
12.08.2020 •
Mathematics
If 24, x, and 6 form the first three terms of an arithmetic sequence
then which of the following is the value of x?
(1) 12
(3) 20
(2) 15
(4) 42
Solved
Show answers
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Ответ:
Work Shown:
d = common difference
p = first term = 24
q = second term = a+d = 24+d
r = third term = q+d = 24+d+d = 24+2d = 6
Solve for d
24+2d = 6
2d = 6-24
2d = -18
d = -18/2
d = -9
We add -9 to each term to get the next term. This is the same as subtracting 9 from each term to get the next term.
First term = 24
Second term = 24-9 = 15
Third term = 15-9 = 6
We get the sequence 24, 15, 6
Ответ:
Hi!
Assuming the 9in is the radius, we would multiply it by 2, or add it to itself. We then get 18 in.
Hope this helps!