If 2sinAcosBsinC=sinBsin(A+C) then tanA,tanB,tanC are in

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Riley3833

26.09.2021

Mathematics

For this case we have, by definition:

$a^{-b} =\frac{1}{a ^ b}$

So, we have:

$\frac{1}{4}^{-\frac{1}{2}}=\frac{1}{(\frac{1}{4})^{\frac{1}{2}}}$

On the other hand we have that by definition:

$a^{\frac{1}{2}}=\sqrt{a}$

Thus, the expression can be written as:

$\frac{1}{\sqrt {\frac{1}{4}}} =$

$\frac{1}{\frac{1}{\sqrt{4}}}$

$\frac{1}{\frac{1}{2}}$

$\frac{1*2}{1*1}=2$

So, we have:

$\frac{1}{4}^{-\frac{1}{2}}= 2$

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