Mathematics: If 3x2 – x + 9 = 0, what are the values of x?

If 3x2 – x + 9 = 0, what are the values of x?

Zshotgun33

16.01.2022

$x=\frac{1+i\sqrt{107} }{6}$

$x=\frac{1-i\sqrt{107} }{6}$

Step-by-step explanation:

3x^2 - x + 9 = 0

To solve for x we use quadratic formula

$x=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

The value of a=3, b=-1 and c=9

Plug in the values in the formula and solve for x

$x=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

$x=\frac{1+-\sqrt{(-1)^2-4(3)(9)} }{2(3)}$

$x=\frac{1+-\sqrt{-107} }{6}$

The value of square root (-1) is 'i'

$x=\frac{1+i\sqrt{107} }{6}$

$x=\frac{1-i\sqrt{107} }{6}$

0,0(0 оценок)