Mathematics: If 4x^2 - 100 = 0 then the roots of the equation are

If 4x^2 - 100 = 0 then the roots of the equation - id4210001816745, lujaynsparkles

Ответ:

melany682296

31.12.2021

4x² - 100 = 0
     + 100 + 100
   4x² = 100
      4 4
   x² = 25
      x = +5
4(5)² - 100 = 0
4(25) - 100 = 0
100 - 100 = 0
   0 = 0

4(-5)² - 100 = 0
4(25) - 100 = 0
   100 - 100 = 0
      0 = 0

The roots of the equation is positive or negative 5.

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Ответ:

anitadefrances

20.03.2023

Mathematics

$\frac{ 4}{x + 1} - \frac{1}{x} = 1 \\ \\x+1\neq 0 \ \ \ and \ \ \ x\neq 0 \\ \\x\neq -1 \ \ \ and \ \ \ x\neq 0 \\ \\D=R\setminus \left \{ -1,0 \right \}$

$\frac{ 4x- (x+1)}{x(x + 1)} = 1 \\ \\\frac{ 4x- x-1 }{x^2+ x}=1 \\ \\\frac{ 3x -1 }{x^2 + x} = 1 \\ \\3x-1=x^2+x\\ \\ x^2+x-3x+1=0$

$x^2-2x+1=0 \\ \\ (x-1)^2=0 \\ \\x-1=0 \\ \\x=1$

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If 4x^2 - 100 = 0 then the roots of the equation are

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