If 5x−4y=22 and 3x+6y=30, what is the value of x−5y

-4 See Below:

Step-by-step explanation:

When you have a system of equations, you need to solve for one variable, and subsitute that variable into the other equation to solve for the other variables value.

3x +6y = 30 In this case, it would be easier to solve for x.

3x= 30-6y  Divide both sides by 3

x= 10-2y

Now we substitute for x in the other equation.

5x- 4y = 22

5(10-2y)-4y=22

50-10y-4y=22

50-14y=22 Add 14y to both sides

50= 14y + 22 Subtract 22 from both sides

28 = 14y     Divide by 14 on both sides.

y = 2

Substitute y=2 and solve for x.

x = 10- 2y

x= 10-2*2

x= 10-4

x= 6

Now we know y=2 and x=6, so we can substitute them into x-5y to find its value.

x - 5y

= 6-5*2

=6-10

= -4

  no

Step-by-step explanation:

You have two congruent angles and the side between them. You can use the ASA Postulate to claim the triangles are congruent.

The SAS Postulate requires two congruent sides (there are 2 instances of S in the name SAS). You don't have that, so the SAS postulate cannot be used.