If a = 4 and b = 6, then c =

answer is 20

Step-by-step explanation:

c2=a2+b2

c2=4*2+6*2

c2=8+12

c=20

depends. if the problem is ab = c then c = 24 but if the problem is a + b = c then c = 10 and if the problem is a - b = c then c = -2 and if the problem is a/b = c then c = 4/6 so be more specific. what is the problem? then maybe i can help

Step-by-step explanation:

Using the t-distribution, we get that:

The 99% confidence interval estimate of the mean amount of mercury in the population is (0.22 ppm, 1.28 ppm).A. No, because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.

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The observations are: {0.58, 0.82, 0.1, 0.98, 1.27, 0.56, 0.96}

Before building the confidence interval, we need to find the sample mean and the sample standard deviation.

Now, we have the standard deviation for the sample, thus the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 7 - 1 = 6

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of . So we have T = 3.71.

The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.75 - 0.53 = 0.22 ppm

The upper end of the interval is the sample mean added to M. So it is 0.75 + 0.53 = 1.28 ppm.

The 99% confidence interval estimate of the mean amount of mercury in the population is (0.22 ppm, 1.28 ppm).

From this, the correct option for the interpretation is:

A. No, because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.

A similar problem is given at link