If a randomly selected customer was satisfied with his/her meal, what is the probability that the customer ordered fish

87.5%

Step-by-step explanation:

Complete question  -

75% of the people who eat at Doug's Diner order fish and 90% of the people who order fish also order fries. Given that 80% of all people who eat at Doug's order fries, what is the probability that a randomly chosen customer orders fries without fish?

Solution

Given

People who order fish at the Doug's Diner  = 75%

Out of this 75%, 90% also order  fries which means that nearly 67.5% ordered fries with the fish.

Given that, 80% of people dining at Doug's Diner order fries

Then percentage or people who ordered only fires and no fish = 80% - 67.5% = 12.5%

The probability of customers who ordered fish = 100 - 12.5% = 87.5%