If f'(x) = 0 at x = -2, 0, and 2 and f"(x) is shown below
then f has a local maximum at x = ?

How are you supposed to figure that out?

12345678754324567876

The length of the hypotenuse of the triangle will be  √(3²+4²) = √25 = 5then the sine of the angle marked x is   sin(x) = opposite/hypotenuse = 3/5the cosine of the angle marked y is   cos(y) = adjacent/hypotenuse = 3/5in a right triangle, sin(x) = cos(y), and sin(y) = cos(x).the relationship the ratios share is that they are equal.