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cameron12502
30.08.2019 •
Mathematics
If f(x) = 1 – x, which value is equivalent to |f(i)|?
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Ответ:
f(i) = 1 - i
|f(i)| = √(1² + (-1)²) = √(1 + 1) = √2
Ответ:
If f(x) = 1 – x then, value of |f(i)| is:
√2
Step-by-step explanation:
f(x) = 1 – x
Then, f(i) = 1 - i
We know that if f(z)=x+iy then, |f(z)|=![\sqrt{x^2+y^2}](/tpl/images/0210/9965/c7b7f.png)
Hence, |f(i)| =![\sqrt{1^2+(-1)^2}](/tpl/images/0210/9965/242b3.png)
=![\sqrt{1+1}](/tpl/images/0210/9965/bba37.png)
= √2
Hence, if f(x) = 1 – x then, value of |f(i)| is:
√2
Ответ:
If you have another equation, then you would plug in y - 1 into the x value of the equation you would need to substitute into.
Hope this helps