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pgfrkypory2107
27.07.2020 •
Mathematics
If f'(x) = 12x^3 - 2x^2 - 17 and f(1) = 8 , find f(x).
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Ответ:
f(x) = 3x⁴ -
- 17x + ![\frac{68}{3}](/tpl/images/0713/5863/3d049.png)
Step-by-step explanation:
To find f'(x), we will follow the steps below:
We will start by integrating both-side of the equation
∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx
f(x) = 3x⁴ -
- 17x + C
Then we go ahead and find C
f(1) = 8
so we will replace x by 1 in the above equation and solve for c
f(1) = 3(1)⁴ -
- 17(1) + C
8 = 3 -
- 17 + C
C =8 - 3 + 17 +![\frac{2}{3}](/tpl/images/0713/5863/d1391.png)
C = 22 +![\frac{2}{3}](/tpl/images/0713/5863/d1391.png)
C =![\frac{66 + 2}{3}](/tpl/images/0713/5863/d8d32.png)
C =![\frac{68}{3}](/tpl/images/0713/5863/3d049.png)
f(x) = 3x⁴ -
- 17x + ![\frac{68}{3}](/tpl/images/0713/5863/3d049.png)
Ответ:
HOPE IT HELPS