lizzyhearts
27.07.2019 •
Mathematics
If f(x) =2x^2-2-10 what is the value of f(1) to the nearest tenth of necessary
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Ответ:
f(1) = 2(1)² - 2 - 10
= 2 - 2 - 10
= -10
Therefore, the answer is -10.
Ответ:
34
Step-by-step explanation:
7 times 4 +28
28+6 = 34
so i simplified...
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I hope this helped!!