Mathematics: If h(x) = (fog)(x) and h(x) = 4(x+1)^2, find one possibility for f(x) and g(x).

If h(x) = (fog)(x) and h(x) = 4(x+1)^2, find one

Ответ:

eylinglez3ovm16v

02.01.2022

Mathematics

Option C

Step-by-step explanation:

We will check all the options one by one to see which group of function produces h(x)

Option A:

$f(x) = x+1\\g(x) = 4x^2\\(fog)(x) = g(x) + 1\\= 4x^2+1$

Not correct..

Option B:

$f(x) = 4x^2\\g(x)=(x+1)^2\\(fog)(x) = 4(g(x))^2\\= 4[(x+1)^2]^2$

Not Correct

Option C:

$f(x) = 4x^2\\g(x) = x+1\\(fog)(x) = 4(g(x))^2\\= 4(x+1)^2$

The composition is same as h(x) so it is the correct answer ..

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Ответ:

kellyzeissss4181

21.07.2022

Mathematics

X-intercepts
f(x) = 0

4x² - 15x - 4 = 0

4x² - 16x + x - 4 = 0

4x(x - 4) + 1(x - 4) = 0

(x - 4)(4x + 1) = 0 ⇔ x - 4 = 0 or 4x + 1 = 0

x = 4 or 4x = - 1 ⇒ x = - 1/4

-1/4 and 4.

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If h(x) = (fog)(x) and h(x) = 4(x+1)^2, find one possibility for f(x) and g(x).

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