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12.08.2020 •
Mathematics
If m(2x−3)+n(x+1)=5x for all real numbers x, where m and n are constants, what is the value of m?
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Ответ:
m = 1
Step-by-step explanation:
From the question given,
m(2x − 3) + n(x + 1) = 5x for all real numbers x.
Since x is a real number, we can obtain the value of m as follow:
Let x = 1
m(2x − 3) + n(x + 1) = 5x
m(2×1 − 3) + n(1 + 1) = 5×1
m(2 – 3) + n(2) = 5
m(– 1) + n(2) = 5
– m + 2n = 5 (1)
Let x = 2
m(2x − 3) + n(x + 1) = 5x
m(2×2 − 3) + n(2 + 1) = 5×2
m(4 – 3) + n(3) = 10
m(1) + n(3) = 10
m + 3n = 10 (2)
– m + 2n = 5 (1)
m + 3n = 10 (2)
Solve by elimination method
Add equation 1 and 2
– m + 2n = 5
+ (m + 3n = 10)
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
5n = 15
Divide both side by 5
n = 15/5
n = 3
Substitute the value of n into any of the equation to obtain the value of m. Here, we shall substitute n into equation 2.
m + 3n = 10
m + 3(3) = 10
m + 9 = 10
Collect like terms
m = 10 – 9
m = 1
Therefore, the value of m is 1
Ответ:
Random assignment refers to the use of chance procedures in psychology experiments to ensure that each participant has the same opportunity to be assigned to any given group. Study participants are randomly assigned to different groups, such as the experimental group or treatment group.