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anessia83
23.02.2020 •
Mathematics
If M is a two digit number and N is obtained by reversing M, if M+N =132, how many values can M have?
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Ответ:
7
Step-by-step explanation:
Let M be a two digit number with x in the tens position and y in units:
M = 10x + y
Then N will have y in the tens position and x in units:
N = 10y + x
M+N = 10x + y + 10 + x = 132
11x + 11y = 132
11(x + y) = 132
x + y = 12
x and y are single digit whole numbers. Possible combinations are:
x = 3 y = 9
x = 4 y = 8
x = 5 y = 7
x = 6 y = 6
x = 7 y = 5
x = 8 y = 4
x = 9 y = 3
Values of M can be:
39, 48, 57, 66, 75, 84, 93
Which are 7
Ответ: