If m2 = 7x + 7, m3 = 4y, and m4 = 112, find the values of x and y

M2 x 2 = m4
soo m2 now becomes m4 = 14x + 14
112 = 14x + 14
subtract 14 from both sides
98 = 14x
divide by 14 on both sides 
7 = x

to find Y, 12 is the lowest number you can make 3 & 4
so multiply m3 by 4 and m4 by 3
so instead of m3 = 4y and m4 = 112 it now becomes
m12 =16y and m12 = 336
16Y = 336
divide both sides by 16 
Y = 21

Her method will produce a valid sample.

Her method will produce a random sample.

Her method will produce a representative sample.

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