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29.01.2020 •
Mathematics
If one of two positive integers is 7 less than the other, and the product of the two integers is 78, find the integers.
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Ответ:
Let the greater integer be x
Then other integer= x-7
A/q- x(x-7)= 78
=> x^2 -7x-78=0
=> x^2 -13x +6x -78=0
=> x (x-13) +6 (x-13)=0
=> (x-13)(x+6)= 0
So, x=13 or x= -6
since -6 is not a positive integer so the value of
x=13
other integer= x-7=13-7=6
Hence, the numbers are 13 and 6
HOPE IT IS USEFUL
Ответ:
Id k this I’m in middle school
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