If tan theta=3/4, find sin theta

sin(theta)=3/5

Step-by-step explanation:

tan(theta)=3/4

sec^2(theta)=1+tan^2(theta)=1+(3/4)^2=1+9/16=(16+9)/16=25/16

sec(theta)=square root of(25/16)=5/4

sec(theta)=1/cos(theta)=5/4

cos(theta)=4/5

sin^2(theta)=1-cos^2(theta)=1–16/25=(25–16)/25=9/25

sin(theta)=3/5

So

sec(theta)=5/4

sin(theta)=3/5

The answer would be 6 irises bloomed last year.

Step-by-step explanation:

let x represent the # of flowers bloomed last year

15% =  .15

now just use the equation: quantity = % · whole and plug in the #'s      

                                                                            x  = .15 · 40

which equals to x = 6

i hope this helps! :)