Mathematics: If the area of a square is 38 less than 2 times the area of a hexagon, and the sum of the areas of the square and hexagon is 46, what are the areas of the square and hexagon?

If the area of a square is 38 less than 2 times

Ответ:

bwright142

11.03.2022

$\bf \begin{cases}
s=\textit{area of the square}\\
h=\textit{area of the hexagon}
\end{cases}
\\\\\\
\textit{38 less than 2 times the area of a hexagon}\implies \boxed{s}=2h-38
\\\\\\
\textit{we also know that their sum is }\implies s+h=46
\\\\\\
\boxed{2h-38}+h=46\implies 3h=46+38\implies 3h=84
\\\\\\
h=\cfrac{84}{3}\implies h=28$

what's the area of the square? well, s = 2h - 38.

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Ответ:

nicoleskertich

15.04.2020

Mathematics

Count the rise and run to find the slope, 1. Next, find the y-intercept-(-1). Now make the slope-intercept equation- y = 1x - 1. Double check, put x = 2 in the equation- y = 1(2) - 1 (=) y = 2 - 1 (=) y = 1.

So, the slope-intercept equation for this line is y = 1x - 1.

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If the area of a square is 38 less than 2 times the area of a hexagon, and the sum of the areas of the square and hexagon is 46, what are the areas of the square and hexagon?

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