If the average (arithmetic mean) of x, y, and 20

Ответ:

diawia

19.01.2022

The average of x and y is 95.

Step-by-step explanation:

Given : If the average (arithmetic mean) of x, y, and 20 is 10 greater than the average of x, y, 20, and 30.

To find : What is the average of x and y?

Solution :

Average is the sum of observation divided by number of observation.

According to question,

$\frac{x+y+20}{3}=10+(\frac{x+y+20+30}{4})$

$\frac{x+y+20}{3}=\frac{40+x+y+20+30}{4}$

$\frac{x+y+20}{3}=\frac{x+y+90}{4}$

4(x+y)-3(x+y)=3(90)-20(4)

x+y=190

Divide equation by 2,

$\frac{x+y}{2}=\frac{190}{2}$

$\frac{x+y}{2}=95$

Therefore, the average of x and y is 95.

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