cpools311
08.06.2021 •
Mathematics
If the equation 2x2+bx+5=0 has no real solutions, which of the following must be true?
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Ответ:
There are no choices but in order to qudratic equation not to have real roots the discriminant must be negative.
d = b² - 2*2*5 = b² - 20If d < 0, we get:
b² - 20 < 0b² < 20b < |√20|- √20 < b < √20or
-2√5 < b < 2√5or
b = (-2√5, 2√5)Ответ: