Mathematics: If the length of one side of a square is triple and the length of an adjacent side is increased by 10, the resulting rectangle has an area that is 6 times the area of the original square. find the length of a side pf the original square.

x = -20 X t-2 = CStep-by-step explanation:...

If the length of one side of a square is triple

woodfordmaliky

10.01.2022

Step-by-step explanation:

Given: If the length of one side of a square is triple and the length of an adjacent side is increased by .

To Find: If area is times the area of original square find length of a side of original square.

Solution:

Let the side of original square be $=\text{x}$

area of original square $=\text{x}^2$

when length of side is tripled,

new length of one side of square $=3\text{x}$

length of other side is increased by 10 unit

new length of other side of square $=\text{x}+10$

new area of resulting rectangle $=\text{length of one side}\times\text{length of other side}$

$=(\text{x}+10)\times(3\text{x})$

$3\text{x}^{2}+30$

As area of resulting rectangle is 6 times the original square

$3\text{x}^{2}+30=6\text{x}^2$

$3\text{x}^2-30=0$

$3\text{x}(\text{x}-10)=0$

$\text{x}=10,0$

as length cannot be zero

$\text{x}=10$

Hence the length of a side of original square is

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