If using the method of completing the square to solve the quadratic equation x2 + 7x + 10 = 0, which number would have to be added to "complete the
square"?

x² + 7x + 10 = 0

Subtract 10 from both sides

x² + 7x = -10

Use half the x coefficent (7/2) as the complete the square term

(x + 7/2)² = -10 + (7/2)²

   note: the number added to "complete the square" is (7/2)² = 49/4

(x + 7/2)² = -10 + 49/4

(x + 7/2)² = 9/4

Take the square root of both sides

x + 7/2 = ±3/2

Subtract 7/2 from both sides

x = -7/2 ± 3/2

x = {-5, -2}

It is -4,8.

Step-by-step explanation:

y=2x +16

{

-7y=-2x-64

-6y=-48

y=8 then using substitution you will get x=-4