Mathematics: If we know that the length of time it takes a college student to find a parking spot in the library parking lot follows a normal distribution with a mean of 3.5 minutes and a standard deviation of 1 minute, find the probability that a randomly selected college student will take between 2 and 4.5 minutes to find a parking spot in the library parking lot, rounding to four decimal places.

If we know that the length of time it takes a

Ответ:

austinwag123

08.01.2022

0.7745

Step-by-step explanation:

Given : The length of time it takes a college student to find a parking spot in the library parking lot follows a normal distribution with $\mu=3.5$ minutes and $\sigma=1$ minute.

Let x represents the time to find a parking spot in the library parking lot.

Since , $z=\dfrac{x-\mu}{\sigma}$

z-score corresponds x = 2 , $z=\dfrac{2-3.5}{1}=-1.5$

z-score corresponds x = 4.5 , $z=\dfrac{4.5-3.5}{1}=1$

Required probability :

$\text{P-value }: P(2$

[using z-value table.]

Hence, the probability that a randomly selected college student will take between 2 and 4.5 minutes to find a parking spot in the library parking lot, (rounding to four decimal place )= 0.7745

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Ответ:

kosta42

17.10.2022

Mathematics

x = $-\frac{41}{19}$

y = $\frac{7}{19}$

Step-by-step explanation:

2x = 10y - 8

3x + 4y + 5 = 0

2x = 10y - 8

x = 5y - 4

3x + 4y + 5 = 0

3 ( 5y - 4 ) + 4y + 5 = 0

19y - 7 = 0

19y = 7

y = $\frac{7}{19}$

x = 5y - 4

x = 5 ( $\frac{7}{19}$ ) - 4

x = $-\frac{41}{19}$

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