Mathematics: If , x - 12 square root of x + 36 = 0what is the value of x? a. 6 b. 6^2 c. 6^3 d. 6^4

If , x - 12 square root of x + 36 = 0what is the value

irene003

15.01.2022

Option B) 6^2 is correct.

That is in the given equation $x-12\sqrt{x}+36=0$ the value of x is 6^2

ie., x=6^2

Step-by-step explanation:

The given equation is $x-12\sqrt{x}+36=0$

To find the value of x in the given equation :

$x-12\sqrt{x}+36=0$

Rewritting the above equation as below :

$\sqrt{x}^2-2(\sqrt{x})(6)+6^2=0$

Which is in the form of (a-b)^2=a^2-2ab+b^2

Here $a=\sqrt{x}$ and b=6

Therefore it can be written as

$(\sqrt{x}-6)^2=0$

$\sqrt{x}-6=0$

$\sqrt{x}=6$

Squaring on both sides we get

$(\sqrt{x})^2=6^2$

x=6^2

Therefore in the given equation $x-12\sqrt{x}+36=0$ the value of x is 6^2

Therefore Option B) 6^2 is correct.

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graymonky12

08.01.2023

1.5 hours

Step-by-step explanation:

Divide 514 by 338 to get 1.5207 and round it to 1.5 because we are working with time

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