If x^2 -7x=30 and x>0, what is the value of x-5

5

Step-by-step explanation:

x^2-7x=30

x^2-7x-30=0

a = 1, b = -7, c = -30

sqrt(b^2-4ac)

sqrt(49+120)

sqrt(169)

13

-b +/- 13

7 + 13 = 20

7 - 13 = -6

2a = 2

20/2 = 10

-6/2 = -3

we know x>0, so it cant be -3. so now its just 10 - 5

x=8

Step-by-step explanation:

This isosceles triangle is composed of two right triangles with sides 8, , and y

As we have two sides of a right triangle, we can find the third using the Pythagorean Theorem

As this is an isosceles triangle, these two right triangles are equal, this means that x=2y

Therefore, x=2(4)=8