notcollin2416
10.11.2021 •
Mathematics
If x+y= -4 and xy=2, then find the value of x²+y²
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Ответ:
x² + y² = 12
Step-by-step explanation:
x + y = -4
xy = 2
x² + y² = (x+y)² - 2xy = (-4)² - 2(2) = 16 - 4 = 12
Ответ:
Xy=2
(x+y)^2= x^2+y^2+2xy
(-4)^2=x^2+y^2+2(2)
16 = x^2+y^2+4
x^2+y^2=16-4
Therefore x^2+y^2 = 12
Ответ:
Step-by-step explanation: