If you could pick the same number twice and the first numbers is odd and less than 5, then the probability that the sum of the two numbers is lessthan 5 is

The 1st number is odd, less than 5, so it might be 1 or 3, the probability is 2/10
But if the sum has to less than 5, than *when 1st number is 1, the second number can only be 1.2.3
and *when 1st number is 3, 2nd can only be 1
*1: 3/100
*2: 1/100
3/100+1/100=4/100
so the answer should be (4/100)/(2/10)=2/10=1/5
I'm not so sure if I'm right
plz tell me if there's something wrong with my answer

55?

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