Mathematics: Ignore the circled one and actually try please

Ignore the circled one and actually try please

Ответ:

drainy0uandthefish

28.01.2022

a. $\frac{x^3-4x^2}{3x+15}$

Step-by-step explanation:

$\huge{ \frac{2x^4}{x+5} \div \frac{6x^2}{x-4} }\\\\\huge{= \frac{2x^4}{x+5} \times \frac{x-4}{6x^2}}\\\\\huge{ =\frac{x^2}{x+5} \times \frac{x-4}{3}}\\\\\huge {=\frac{x^2(x-4)}{3(x+5)}}\\\\\huge{=\frac{x^3-4x^2}{3x+15}}$

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Ignore the circled one and actually try please

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