brooklyn4932

29.01.2020 • 

Mathematics

Ihave 3 pieces of candy to place in 4 lunch boxes. in how many ways can i do this if:

(a) the candies are all different and the lunch boxes are all different?

(b) the candies are all the same and the lunch boxes are all the same?

(c) the candies are all the same and the lunch boxes are all different?

(d) the candies are all different and the lunch boxes are all the same?

(e) exactly two of the candies are the same (but the third is different) and all of the lunch boxes are different?

Ответ:

Arealbot

19.06.2020

Mathematics

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  a. each candy has 4 choices, so 4^3 = 64

b. using the stars and bars formula, (3+4-1)C3 = 6c3 = 20

c. in 1 box , in 2 boxes or 3 boxes: 3c3 +3c2 + 3c1 = 7

d. in 1 box, 2 boxes or 3 boxes = 3

e. in 1 box (4) , in 2 boxes : 2combos (AA|B & AB|A) distributed to boxes in 4!/2! ways, and 1 each a box distributed to boxes in 4!/2! ways = 4+24+12 = 40 ways

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Ответ:

yeroo860

19.06.2020

Mathematics

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The answer is 40. Hope that helped

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Ответ:

chloerodgers56

25.03.2020

Mathematics

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y=2x-4

Step-by-step explanation:

you have to solve for y and so you would subract 2x and move it to the side with the 4 and the y would be negative so you would divide by negative 1 to get the answer

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