Mathematics: In a certain state, a survey of 600 workers showed that 35% belonged to a union. Find the 95% confidence interval of true proportion of workers who belong to a union.

In a certain state, a survey of 600 workers showed

eva4548

16.03.2022

The 95% confidence interval of true proportion of workers who belong to a union.

(0.29657 , 0.40343)

Step-by-step explanation:

Explanation:-

Given sample size 'n' = 600

Given sample proportion p = 35% or 0.35

The 95% confidence interval of true proportion of workers who belong to a union.

$(p^{-} -Z_{0.05} \sqrt{\frac{pq}{n} } , p^{-} + Z_{0.05} \sqrt{\frac{pq}{n} } )$

$(0.35 -1.96\sqrt{\frac{0.35 X0.65}{600} } , 0.35 + 1.96\sqrt{\frac{0.35 X 0.65}{600} } )$

( 0.35 - 1.96 (0.02726) , 0.35 + 1.96 (0.02726)

(0.35 - 0.05343 , 0.35 + 0.05343)

(0.29657 , 0.40343)

Final -

The 95% confidence interval of true proportion of workers who belong to a union.

(0.29657 , 0.40343)

0,0(0 оценок)

BriTheKueen

26.04.2020

Step-by-step explanation:

Putting values of x y and z in the expression

2(1) - [(1)(4) + 1]2 - (-2)

2 - (4+1)2 + 2

2 - (5)2 + 2

2 - 25 + 2

-23 + 2

-21

0,0(0 оценок)